一、 漏洞 CVE-2025-6122 基础信息
漏洞信息
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漏洞标题
code-projects Restaurant Order System table.php sql injection
来源:美国国家漏洞数据库 NVD
漏洞描述信息
A vulnerability, which was classified as critical, was found in code-projects Restaurant Order System 1.0. This affects an unknown part of the file /table.php. The manipulation of the argument ID leads to sql injection. It is possible to initiate the attack remotely. The exploit has been disclosed to the public and may be used.
来源:美国国家漏洞数据库 NVD
CVSS信息
CVSS:3.1/AV:N/AC:L/PR:L/UI:N/S:U/C:L/I:L/A:L
来源:美国国家漏洞数据库 NVD
漏洞类别
SQL命令中使用的特殊元素转义处理不恰当(SQL注入)
来源:美国国家漏洞数据库 NVD
二、漏洞 CVE-2025-6122 的公开POC
# POC 描述 源链接 神龙链接
三、漏洞 CVE-2025-6122 的情报信息
  • 标题: code-projects Restaurant Order System Project V1.0 /table.php SQL injection · Issue #3 · ez-lbz/poc -- 🔗来源链接

    标签: exploit issue-tracking

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  • 标题: Download Free Open Source Projects | PHP, C++ | Source code & Projects -- 🔗来源链接

    标签: product

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  • 标题: Login required -- 🔗来源链接

    标签: signature permissions-required

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  • 标题: Submit #592624: code-projects Restaurant Order System V1.0 SQL injection -- 🔗来源链接

    标签: third-party-advisory

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  • 标题: CVE-2025-6122 code-projects Restaurant Order System table.php sql injection (EUVD-2025-18395) -- 🔗来源链接

    标签: vdb-entry technical-description

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  • 标题: Submit #592617: code-projects Restaurant Order System V1.0 SQL injection -- 🔗来源链接

    标签: third-party-advisory

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  • https://nvd.nist.gov/vuln/detail/CVE-2025-6122