来源

关联漏洞

描述

PHP-FPM Remote Code Execution Vulnerability (CVE-2019-11043) POC in Python

介绍

# CVE-2019-11043
1.漏洞描述
Nginx上fastcgi split path info 在处理带有%0a的请求时,会因为遇到换行符\n导致PATH INFO为空。而php-fpm在处理PATH INFO为空的情况下，存在逻辑缺陷。攻击者通过精心的构造和利用，可以导致远程代码执行。

影响范围
Nginx + php-fpm 的服务器,在使用如下配置的情况下，都可能存在远程代码执行漏洞。
location ~ [^ /小.php(/|$) {
fastcgi split path info ^(.+ ?\.php)(.*)$;
fastcgi param PATH INFO $fastcgi path info;fastcgi pass php:9000;
}

2.漏洞检测
方案一：利用 phuip-fpizdam脚本检测

0x01 安装 phuip-fpizdam-Mac
go get github.com/neex/phuip-fpizdam
go install github.com/neex/phuip-fpizdam
➜  ~ cd ./go
➜  go go get github.com/neex/phuip-fpizdam
➜  go go install github.com/neex/phuip-fpizdam
➜  go ls
bin src
➜  go cd bin
➜  bin ls
phuip-fpizdam
➜  bin file phuip-fpizdam 
phuip-fpizdam: Mach-O 64-bit executable x86_64

➜  bin ls -lah phuip-fpizdam 
-rwxr-xr-x  1 alewong  staff   9.3M 10 24 10:54 phuip-fpizdam

![step 2](https://github.com/AleWong/CVE-2019-11043/blob/master/2.png)
bin ./phuip-fpizdam

Error: accepts 1 arg(s), received 0
Usage:
  phuip-fpizdam [url] [flags]

Flags:

      --cookie string       send this cookie
  -h, --help                help for phuip-fpizdam
      --kill-count int      how many times to send the worker killing payload (default 50)
      --kill-workers        just kill php-fpm workers (requires only QSL)
      --method string       detect method (see detect_methods.go) (default "session.auto_start")
      --only-qsl            stop after QSL detection, use this if you just want to check if the server is vulnerable
      --pisos int           pisos hint
      --qsl int             qsl hint
      --reset-retries int   how many retries to do for --reset-setting, -1 means a lot (default 50)
      --reset-setting       try to reset setting (requires attack params)
      --setting string      specify custom php.ini setting for --reset-setting
      --skip-attack         skip attack phase
      --skip-detect         skip detection phase
2019/10/24 10:56:18 accepts 1 arg(s), received 0



0x03 检验目标网址

![step 3](https://github.com/AleWong/CVE-2019-11043/blob/master/3.png)
可以看见返回结果为202，成功

0x04 查看网页情况
![step 4](https://github.com/AleWong/CVE-2019-11043/blob/master/4.png)

![step 5](https://github.com/AleWong/CVE-2019-11043/blob/master/5.png)

方案二 利用python脚本检测
![step 7](https://github.com/AleWong/CVE-2019-11043/blob/master/7.png)

![step 6](https://github.com/AleWong/CVE-2019-11043/blob/master/6.png)
脚本思路：当Q阀值到一定的时候 如1800 会返回502 则可证明漏洞存在

运行结果：
![step 8](https://github.com/AleWong/CVE-2019-11043/blob/master/8.jpeg)

和burpsuite结果一致
![step 9](https://github.com/AleWong/CVE-2019-11043/blob/master/9.png)

文件快照

 [4.0K]  /data/pocs/54edbc563877ceb0c5aafe86f14162d6a6470783
├── [791K]  2.png
├── [825K]  3.png
├── [101K]  4.png
├── [ 92K]  5.png
├── [ 96K]  6.png
├── [717K]  7.png
├── [266K]  8.jpeg
├── [497K]  9.png
├── [1.6K]  CVE-2019-11043.py
└── [2.9K]  README.md

0 directories, 10 files

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