CVE-2014-6271 PoC — GNU Bash 远程代码执行漏洞

Source

https://github.com/352926/shellshock_crawler

Associated Vulnerability

Title:GNU Bash 远程代码执行漏洞 (CVE-2014-6271)
Description:GNU Bash是美国软件开发者布莱恩-福克斯（Brian J. Fox）为GNU计划而编写的一个Shell（命令语言解释器），它运行于类Unix操作系统中（Linux系统的默认Shell），并能够从标准输入设备或文件中读取、执行命令，同时也结合了一部分ksh和csh的特点。 GNU Bash 4.3及之前版本中存在安全漏洞，该漏洞源于程序没有正确处理环境变量值内的函数定义。远程攻击者可借助特制的环境变量利用该漏洞执行任意代码。以下产品和模块可能会被利用：OpenSSH sshd中的ForceComman

Description

Using google to scan sites for "ShellShock" (CVE-2014-6271)

Readme

Prerequisite
============

1. `sudo pip install shell`
2. install google python search.  https://github.com/MarioVilas/google

Run
===
I use google to search first 1000 sites and try to get the `/etc/passwd`
After tesing, there are many many many host that can be rooted!!!!
By the way, this is only a proto, it has false positives.

Output like this:
if second field is `!!!`, then You Can Get SHELL!

```
$ python shellshock.py
0 --- http://nomad3.ncep.noaa.gov/cgi-bin/pdisp_sst.sh
1 --- http://nomad5.ncep.noaa.gov/cgi-bin/pdisp_gfs.sh?ctlfile=gfs_00z.ctl&povlp=noovlp&ptype=map&dir
```

References
===========
http://vonnyfly.github.io/

https://www.invisiblethreat.ca/2014/09/cve-2014-6271/

File Snapshot


 [4.0K]  /data/pocs/5e1ad3143bdca326c0e108db61fdce8b08704f0f
├── [ 697]  README.md
└── [ 950]  shellshock.py

0 directories, 2 files

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