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CWE-1419 类漏洞列表 7

CWE-1419 类弱点 7 条 CVE 漏洞汇总，含 AI 中文分析。

CWE-1419 指资源初始化错误，导致资源处于非预期或不安全状态。攻击者常利用此缺陷，通过操纵未正确初始化的变量（如认证标志）或寄存器，绕过安全校验并获取未授权访问。开发者应避免此类漏洞，需确保所有关键资源在首次使用前均被赋予明确、安全的默认值，并严格验证初始化逻辑的完整性，防止因状态异常引发安全风险。

MITRE CWE 官方描述
CWE：CWE-1419 资源初始化不正确 (Incorrect Initialization of Resource) 英文：产品尝试初始化 (initialize) 一个资源，但未能正确执行此操作，这可能导致该资源在被访问时处于意外的、不正确的或不安全 (insecure) 的状态。 当相关资源被预期具有某些特定属性或值时，这可能会带来安全 (security) 影响。示例包括确定用户是否经过身份验证 (authenticated) 的变量，或确定产品安全 (security) 状态的寄存器 (register) 或熔断器 (fuse) 值。对于软件，当使用隐式初始化 (implicit initialization) 时，即资源未被显式设置为特定值，这种弱点经常发生。例如，在 C 语言中，在栈上分配内存时不一定需要清除 (cleared) 内存，许多脚本语言在变量未显式初始化时使用默认的空值、null 值或零值。对于硬件，这种弱点经常出现在复位值 (reset values) 和熔断器 (fuses) 中。在产品复位后，硬件可能会错误地初始化寄存器。在产品生命周期的不同阶段，熔断器可能被设置为错误的值。即使熔断器被设置为正确的值，通往熔断器的线路也可能断开，或者熔断器线路上的硬件可能会改变熔断器值，使其不正确。
常见影响 (3)
ConfidentialityRead Memory, Read Application Data, Unexpected State
Authorization, IntegrityGain Privileges or Assume Identity
OtherVaries by Context
The technical impact can vary widely based on how the resource is used in the product, and whether its contents affect security decisions.
缓解措施 (4)
ImplementationChoose the safest-possible initialization for security-related resources.
ImplementationEnsure that each resource (whether variable, memory buffer, register, etc.) is fully initialized.
ImplementationPay close attention to complex conditionals or reset sources that affect initialization, since some paths might not perform the initialization.
Architecture and DesignEnsure that the design and architecture clearly identify what the initialization should be, and that the initialization does not have security implications.
代码示例 (2)
Consider example design module system verilog code shown below. The register_example module is an example parameterized module that defines two parameters, REGISTER_WIDTH and REGISTER_DEFAULT. Register_example module defines a Secure_mode setting, which when set makes the register content read-only and not modifiable by software writes. register_top module instantiates two registers, Insecure_Devi…
// Parameterized Register module example // Secure_mode : REGISTER_DEFAULT[0] : When set to 1 register is read only and not writable// module register_example #( parameter REGISTER_WIDTH = 8, // Parameter defines width of register, default 8 bits parameter [REGISTER_WIDTH-1:0] REGISTER_DEFAULT = 2**REGISTER_WIDTH -2 // Default value of register computed from Width. Sets all bits to 1s except bit 0 (Secure _mode) ) ( input [REGISTER_WIDTH-1:0] Data_in, input Clk, input resetn, input write, output reg [REGISTER_WIDTH-1:0] Data_out ); reg Secure_mode; always @(posedge Clk or negedge resetn) if (~
Bad · Verilog
register_example #( .REGISTER_WIDTH (32), .REGISTER_DEFAULT (1225) // Correct default value set, to enable Secure_mode ) Secure_Device_ID_example ( .Data_in (Data_in), .Data_out (Secure_reg), .Clk (Clk), .resetn (resetn), .write (write) );
Good · Verilog
This code attempts to login a user using credentials from a POST request:
// $user and $pass automatically set from POST request if (login_user($user,$pass)) { $authorized = true; } ... if ($authorized) { generatePage(); }
Bad · PHP
$user = $_POST['user']; $pass = $_POST['pass']; $authorized = false; if (login_user($user,$pass)) { $authorized = true; } ...
Good · PHP
CVE ID标题CVSS风险等级Published
CVE-2026-33773 Juniper Networks Junos OS 安全漏洞 — Junos OS 5.8 Medium2026-04-09
CVE-2026-21913 Juniper Networks Junos OS 安全漏洞 — Junos OS 7.5 High2026-01-15
CVE-2025-53800 Microsoft Graphics Component 安全漏洞 — Windows 10 Version 1607 7.8 High2025-09-09
CVE-2024-57375 Andamiro Pump It Up 20th Anniversary 安全漏洞 — Pump It Up 2.4 Low2025-04-25
CVE-2024-0103 NVIDIA Triton Inference Server 安全漏洞 — NVIDIA Triton Inference Server 5.4 Medium2024-06-13
CVE-2023-45085 SoftIron HyperCloud 安全漏洞 — HyperCloud 3.2 Low2023-12-05
CVE-2023-5078 Lenovo ThinkPad BIOS 安全漏洞 — ThinkPad BIOS 6.7 Medium2023-11-08

CWE-1419 是常见的弱点类别，本平台收录该类弱点关联的 7 条 CVE 漏洞。