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CWE-835 不可达退出条件的循环(无限循环) 类漏洞列表 289

CWE-835 不可达退出条件的循环(无限循环) 类弱点 289 条 CVE 漏洞汇总,含 AI 中文分析。

CWE-835属于逻辑缺陷类漏洞,指程序包含无法到达退出条件的循环,导致无限执行。攻击者通常利用此缺陷发起拒绝服务攻击,通过触发无限循环耗尽服务器CPU资源或内存,使合法用户无法访问服务。开发者应避免此类问题,需确保循环变量在每次迭代中正确更新,并设置合理的边界检查或超时机制,保证循环最终能正常终止。

MITRE CWE 官方描述
CWE:CWE-835 具有不可达退出条件的循环('Infinite Loop') 英文:该产品包含一个迭代或循环,其退出条件无法被到达,即无限循环。
常见影响 (1)
Availability DoS: Resource Consumption (CPU), DoS: Resource Consumption (Memory), DoS: Amplification
An infinite loop will cause unexpected consumption of resources, such as CPU cycles or memory. The software's operation may slow down, or cause a long time to respond.
代码示例 (2)
In the following code the method processMessagesFromServer attempts to establish a connection to a server and read and process messages from the server. The method uses a do/while loop to continue trying to establish the connection to the server when an attempt fails.
int processMessagesFromServer(char *hostaddr, int port) { ... int servsock; int connected; struct sockaddr_in servaddr; // create socket to connect to server servsock = socket( AF_INET, SOCK_STREAM, 0); memset( &servaddr, 0, sizeof(servaddr)); servaddr.sin_family = AF_INET; servaddr.sin_port = htons(port); servaddr.sin_addr.s_addr = inet_addr(hostaddr); do { // establish connection to server connected = connect(servsock, (struct sockaddr *)&servaddr, sizeof(servaddr)); // if connected then read and process messages from server if (connected > -1) { // read and process messages ... } // keep tr
Bad · C
int processMessagesFromServer(char *hostaddr, int port) { ... // initialize number of attempts counter int count = 0; do { // establish connection to server connected = connect(servsock, (struct sockaddr *)&servaddr, sizeof(servaddr)); // increment counter count++; // if connected then read and process messages from server if (connected > -1) { // read and process messages ... } // keep trying to establish connection to the server // up to a maximum number of attempts } while (connected < 0 && count < MAX_ATTEMPTS); // close socket and return success or failure ... }
Good · C
For this example, the method isReorderNeeded is part of a bookstore application that determines if a particular book needs to be reordered based on the current inventory count and the rate at which the book is being sold.
public boolean isReorderNeeded(String bookISBN, int rateSold) { boolean isReorder = false; int minimumCount = 10; int days = 0; // get inventory count for book int inventoryCount = inventory.getIventoryCount(bookISBN); // find number of days until inventory count reaches minimum while (inventoryCount > minimumCount) { inventoryCount = inventoryCount - rateSold; days++; } // if number of days within reorder timeframe // set reorder return boolean to true if (days > 0 && days < 5) { isReorder = true; } return isReorder; }
Bad · Java
public boolean isReorderNeeded(String bookISBN, int rateSold) { ... // validate rateSold variable if (rateSold < 1) { return isReorder; } ... }
Good · Java
CVE ID 标题 CVSS 风险等级 Published
CVE-2021-20270 Red Hat Ansible Automation 安全漏洞 — python-pygments 7.5 - 2021-03-23
CVE-2021-3416 QEMU 安全漏洞 — QEMU 3.2 - 2021-03-18
CVE-2021-25673 Siemens SIMATIC 安全漏洞 — SIMATIC S7-PLCSIM V5.4 5.5 - 2021-03-15
CVE-2021-20255 QEMU 安全漏洞 — QEMU 5.5 - 2021-03-09
CVE-2018-20803 Mongodb Server 输入验证错误漏洞 — MongoDB Server 6.5 Medium 2020-11-23
CVE-2020-25641 Linux kernel 安全漏洞 — kernel 5.5 - 2020-10-06
CVE-2020-5761 Grandstream HT800 series 安全漏洞 — Grandstream HT800 Series 7.5 - 2020-07-29
CVE-2019-5091 LEAD Technologies LEADTOOLS 安全漏洞 — LEADTOOLS libltdic.so 7.5 - 2019-12-11
CVE-2019-5097 Embedthis Software GoAhead 安全漏洞 — EmbedThis 7.5 - 2019-12-03
CVE-2019-3560 fizz 缓冲区错误漏洞 — fizz 7.5 - 2019-04-29
CVE-2019-3900 Linux kernel 资源管理错误漏洞 — Kernel 7.7 - 2019-04-25
CVE-2019-3833 Openwsman 资源管理错误漏洞 — openwsman 7.5 - 2019-03-14
CVE-2019-3819 Linux kernel 资源管理错误漏洞 — kernel: 4.4 - 2019-01-25
CVE-2018-14621 libtirpc 安全漏洞 — libtirpc 7.5 - 2018-08-30
CVE-2016-9581 OpenJPEG 缓冲区错误漏洞 — openjpeg2 8.1 - 2018-08-01
CVE-2017-2646 Red Hat keycloak 安全漏洞 — keycloak 7.5 - 2018-07-27
CVE-2017-2670 Red Hat Undertow 资源管理错误漏洞 — undertow 7.5 - 2018-07-27
CVE-2018-10912 Red Hat keycloak 安全漏洞 — keycloak 4.9 - 2018-07-23
CVE-2018-1041 Red Hat jboss-remoting 资源管理错误漏洞 — jboss-remoting 7.5 - 2018-02-15

CWE-835(不可达退出条件的循环(无限循环)) 是常见的弱点类别,本平台收录该类弱点关联的 289 条 CVE 漏洞。