漏洞信息
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漏洞
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漏洞信息
A deserialization vulnerability exists in the way parso through 0.4.0 handles grammar parsing from the cache. Cache loading relies on pickle and, provided that an evil pickle can be written to a cache grammar file and that its parsing can be triggered, this flaw leads to Arbitrary Code Execution. NOTE: This is disputed because "the cache directory is not under control of the attacker in any common configuration.
漏洞信息
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漏洞
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漏洞
Parso 代码问题漏洞
漏洞信息
Parso是一款Python解析器。 Parso 0.4.0及之前版本中处理语法的方法存在代码问题漏洞。该漏洞源于网络系统或产品的代码开发过程中存在设计或实现不当的问题。
漏洞信息
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漏洞
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