tracing: Fix memory leak in test_gen_synth_cmd() and test_empty_synth_event()

In the Linux kernel, the following vulnerability has been resolved: tracing: Fix memory leak in test_gen_synth_cmd() and test_empty_synth_event() test_gen_synth_cmd() only free buf in fail path, hence buf will leak when there is no failure. Add kfree(buf) to prevent the memleak. The same reason and solution in test_empty_synth_event(). unreferenced object 0xffff8881127de000 (size 2048): comm "modprobe", pid 247, jiffies 4294972316 (age 78.756s) hex dump (first 32 bytes): 20 67 65 6e 5f 73 79 6e 74 68 5f 74 65 73 74 20 gen_synth_test 20 70 69 64 5f 74 20 6e 65 78 74 5f 70 69 64 5f pid_t next_pid_ backtrace: [<000000004254801a>] kmalloc_trace+0x26/0x100 [<0000000039eb1cf5>] 0xffffffffa00083cd [<000000000e8c3bc8>] 0xffffffffa00086ba [<00000000c293d1ea>] do_one_initcall+0xdb/0x480 [<00000000aa189e6d>] do_init_module+0x1cf/0x680 [<00000000d513222b>] load_module+0x6a50/0x70a0 [<000000001fd4d529>] __do_sys_finit_module+0x12f/0x1c0 [<00000000b36c4c0f>] do_syscall_64+0x3f/0x90 [<00000000bbf20cf3>] entry_SYSCALL_64_after_hwframe+0x63/0xcd unreferenced object 0xffff8881127df000 (size 2048): comm "modprobe", pid 247, jiffies 4294972324 (age 78.728s) hex dump (first 32 bytes): 20 65 6d 70 74 79 5f 73 79 6e 74 68 5f 74 65 73 empty_synth_tes 74 20 20 70 69 64 5f 74 20 6e 65 78 74 5f 70 69 t pid_t next_pi backtrace: [<000000004254801a>] kmalloc_trace+0x26/0x100 [<00000000d4db9a3d>] 0xffffffffa0008071 [<00000000c31354a5>] 0xffffffffa00086ce [<00000000c293d1ea>] do_one_initcall+0xdb/0x480 [<00000000aa189e6d>] do_init_module+0x1cf/0x680 [<00000000d513222b>] load_module+0x6a50/0x70a0 [<000000001fd4d529>] __do_sys_finit_module+0x12f/0x1c0 [<00000000b36c4c0f>] do_syscall_64+0x3f/0x90 [<00000000bbf20cf3>] entry_SYSCALL_64_after_hwframe+0x63/0xcd

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Linux kernel 安全漏洞

Linux kernel是美国Linux基金会的开源操作系统Linux所使用的内核。 Linux kernel存在安全漏洞，该漏洞源于合成事件测试中未释放缓冲区，可能导致内存泄漏。

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